필터 지우기
필터 지우기

Assign matrix names using for loops in formula

조회 수: 1 (최근 30일)
peterhack
peterhack 2016년 6월 9일
댓글: Stephen23 2016년 6월 9일
Hi,
I was wondering how to get my code shorter and cleaner as I am basically using the same formula.
A = zeros(1,t);
B = zeros(1,t);
C = zeros(1,t);
D = zeros(1,t);
E = zeros(1,t);
for z = 1:1:t
if z == 1
A(:,z) = v1;
B(:,z) = v2;
C(:,z) = v3;
D(:,z) = v4;
E(:,z) = v5;
else
A(:,z) = A(:,z-1)*(1+rf);
B(:,z) = B(:,z-1)*(1+rf);
C(:,z) = C(:,z-1)*(1+rf);
D(:,z) = D(:,z-1)*(1+rf);
E(:,z) = E(:,z-1)*(1+rf);
end
end
However, I am aware of better not to use eval.
But I do not get it working using an cell array like here with names = {'A' 'B' 'C' 'D' 'E'}. vx are just some values, which I coul also loop from an array.
Thanks in advance!
  댓글 수: 1
Stephen23
Stephen23 2016년 6월 9일
You are right to avoid eval, which is almost always a bad idea, especially with trivial looped code like this, no matter how much beginners seem attracted to using it:
The solution is to use indexing. That is all. There is no magic trick, just learn to use the dimensions of ND arrays, or cell arrays, or whatever array suits your needs, and use indexing.

댓글을 달려면 로그인하십시오.

채택된 답변

Jos (10584)
Jos (10584) 2016년 6월 9일
편집: Jos (10584) 2016년 6월 9일
Remember: It is the contents of the variable that should be flexible, not its name!
You will be way better off using arrays (regular, structs, or cells).
ABCDE = zeros(t, 5)
ABCDE(:,1) = [v1 v2 v3 v4 v5] ;
for z = 2:1:t
ABCDE(:,z) = ABCDE(:,z-1) .* (1+rf) ; % not sure what rf is, hence the .*
end

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by