match structures by table
조회 수: 3 (최근 30일)
이전 댓글 표시
Dear All, suppose you have two structures, A and B, where
A.a
A.b
A.c
and
B.1
B.2
B.3
Furthermore you have a table, which matches A to B, for example
1 b
2 a
3 c
bsed on this information, I would like to compute stuff using A and B. Both structures have the same number of fiels (which can all be uniquley matched between A and B). I need something like:
for all *table* rows i:
% computation using A.i, B.i;
end
Is there a good way to solve this in Matlab?
Thanks in advance!
댓글 수: 0
채택된 답변
Stephen23
2016년 5월 24일
편집: Stephen23
2016년 5월 24일
You can do this easily using dynamic fieldnames to access the structures. I do not have a MATLAB version with tables, but this example using a cell array should get you started:
A.a = 1;
A.b = 2;
A.c = 3;
B.x = 4;
B.y = 5;
B.z = 6;
C = {'b','x';'a','y';'c','z'};
out = NaN(size(C,1),1);
for k = 1:size(C,1)
af = C{k,1};
bf = C{k,2};
out(k) = A.(af) + B.(bf);
end
produces the correct result:
>> out
out =
6
6
9
댓글 수: 2
Guillaume
2016년 5월 24일
Or simply:
out = rowfun(@(af, bf) A.(af) + B.(bf), T, 'OutputFormat', 'uniform')
추가 답변 (1개)
Guillaume
2016년 5월 24일
Probably the simplest way is to create a function with two inputs, the two field names. Your function then perform the calculation you want using dynamic field names as per Stephen's answer. You use rowfun to iterate over the rows of the table and call your function:
%in its own file (or as an anonymous function)
function result = somefuncname(structA, structB, fieldA, fieldB)
result = structA.(fieldA) + structB.(fieldB);
end
%if using an anonymous function for somefuncname, then you don't need the funwrapper
%pass A and B straight to the function
funwrapper = @(fieldA, fieldB) somefuncname(A, B, fieldA, fieldB);
result = rowfun(funwrapper, yourtable)
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Structures에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!