I'm tying to limit the length of an equation by doing this.
Al = @(x) 25.5e3+(300*x(1))+(x(1))^2;
Aj = @(x) (tan((2*pi)/9))*((x(1))^2+(100*x(1))+50);
Ak = @(x) (1000*(200*x(1))*(x(1))^2)/(2*tan((2*pi)/9));
func = @(x) x(3)*(47e3-Al+Aj+Ak);
What am I doing wrong?
I've read the guides on function handles etc, but I just cant understand it! I don't think I'm meant to be a programmer but I have to do this unfortunately.
Thanks in advance

 채택된 답변

Kevin Holst
Kevin Holst 2012년 2월 8일

0 개 추천

It looks like this is all that's wrong:
func = @(x) x(3)*(47e3-Al(x)+Aj(x)+Ak(x));
I'm assuming x is a 3 value vector?

댓글 수: 1

Will
Will 2012년 2월 8일
Correct. Thank you. sorry for the stupid questions!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Interactive Control and Callbacks에 대해 자세히 알아보기

질문:

2012년 2월 8일

편집:

2013년 10월 4일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by