Constant number is changing value, why?

조회 수: 1 (최근 30일)
Krish Desai
Krish Desai 2016년 3월 25일
편집: dpb 2016년 3월 25일
So I have a 1 that should print out, but instead only on the first line does 1 print out, for the rest the number keeps changing. Why?
dt=5*10e-5;
timenumber=0;
for t=0:dt:2*dt %99 for 100 graphs
figure;
atom=1;
for ind=1:1920
U=(3*ind+linspace(1,3,3)-3);
Phi= PHI_disp_RBME_ModePlot_N(U);
r=xlocs_full(ind);
omega=(f_disp_RBME(iMode,kPtMode)*2*pi);
k=kappa_space(kPtMode);
spatialphase=k*r;
timephase=omega*t;
displ=Phi*exp(i*((spatialphase)-(timephase)));
xOvito(ind)=xOvito(ind)+magFact*displ(1);
yOvito(ind)=yOvito(ind)+magFact*displ(2);
zOvito(ind)=zOvito(ind)+magFact*displ(3);
header0= 'Timestep:';
header1= 'id';
header2= 'type';
header3='x';
header4='y';
header5='z';
headernum='Number of atoms:';
timenumber=(timenumber+1);
if ind==1
fileName=['dump',num2str(t*2000)];
end;
fid=fopen(fileName,'w');
fprintf(fid, [ header0 '\n']);
fprintf(fid, '%d \n', (timenumber/1920)-1');
fprintf(fid, [headernum '\n']);
fprintf(fid, '%d \n', 1920);
fprintf(fid, [ header1 ' ' header2 ' ' header3 ' ' header4 ' ' header5 '\n']);
fprintf(fid, '%f %f %f %f \n', [1 xOvito yOvito zOvito]');-------------->The one keeps changing
fclose(fid);
end
  댓글 수: 1
Walter Roberson
Walter Roberson 2016년 3월 25일
Which is the value that keeps changing?

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답변 (1개)

dpb
dpb 2016년 3월 25일
편집: dpb 2016년 3월 25일
...
for ind=1:1920
...
xOvito(ind)=xOvito(ind)+magFact*displ(1);
yOvito(ind)=yOvito(ind)+magFact*displ(2);
zOvito(ind)=zOvito(ind)+magFact*displ(3);
... header0= 'Timestep:';
fprintf(fid, '%f %f %f %f \n', [1 xOvito yOvito zOvito]'); % The one keeps changing
...
Because as the above reduced code snippet shows, you're building arrays from 1:1920 for each of the three variables in the loop and the fprintf argument list uses the variable names without subscripting. So, each pass through the loop you'll get first one set of values, then two for each, then three, etc., ... Since the format is for four elements per output record, they'll wrap and the position of each relatively to each other will change each pass.
You undoubtedly intended to write
fprintf(fid, '%f %f %f %f \n', [1 xOvito(ind) yOvito(ind) zOvito(ind)]');
In summary, the '1' didn't change its value, it simply gets placed in a different location owing to the number of values being printed each pass through the loop.
ADDENDUM
While not related to the issue, you'll save quite a lot if you preallocate the three arrays before beginning the loop over ind --
...
xOvito=zeros(1920,1); % preallocate
yOvito=zeros(1920,1); % preallocate
zOvito=zeros(1920,1); % preallocate
for ind=1:1920
...
xOvito(ind)=xOvito(ind)+magFact*displ(1);
yOvito(ind)=yOvito(ind)+magFact*displ(2);
zOvito(ind)=zOvito(ind)+magFact*displ(3);
...

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