Differentiation without symbolic toolbox. Is it possible numerically?
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Suppose I have a function
x = 0:0.1:10;
fxy = @(x,y) x^3 +3*x*y^2 + 2*x
I want differentiate w.r.t 'x'
dfxy = @(y)diff(fxy,1)
and then I want to solve for 'y' for 'dfxy(y) = 0'
y0 = 0.1;
yy = fsolve(dfxy,y0)
is this possible without using symbolic toolbox? I get error like 'Function 'diff' is not supported for class 'function_handle'.'
답변 (2개)
Jakub Rysanek
2017년 1월 31일
편집: Walter Roberson
2017년 1월 31일
0 개 추천
카테고리
도움말 센터 및 File Exchange에서 Symbolic Math Toolbox에 대해 자세히 알아보기
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