Gauss Seidel Iretative Method

조회 수: 25 (최근 30일)
Damian Andreani
Damian Andreani 2016년 3월 8일
답변: Meysam Mahooti 2019년 11월 29일
Hello,
I am a structural engineer and our matrices consist of many 0s. Below is my code for using the Gauss seidel method to solve my matrix formula but I am having trouble when dividing by A(i,i) when A(i,i) is 0.
s = ft_GaussSeidel(A,b)
clear all; close all; clc;
A = [.707 1 0 0 0 0 0 0 0 0 0 0 0;
-.707 0 1 0 0 0 0 0 0 0 0 0 0;
.7071 0 0 1 0 0 0 0 0 0 0 0 0;
0 -1 0 0 .659 1 0 0 0 0 0 0 0;
0 0 0 -1 -.753 0 0 0 0 0 0 0 0;
0 0 -1 0 -.659 0 1 0 0 0 0 0 0;
0 0 0 0 .753 0 0 1 0 0 0 0 0;
0 0 0 0 0 -1 0 0 .659 1 0 0 0;
0 0 0 0 0 0 0 -1 -.753 0 0 0 0;
0 0 0 0 0 0 -1 0 -.659 0 1 0 0;
0 0 0 0 0 0 0 0 .735 0 0 1 0;
0 0 0 0 0 0 0 0 0 -1 0 0 .707;
0 0 0 0 0 0 0 0 0 0 0 -1 -.707];
b = [0;
2000;
-6229;
0;
600;
0;
0;
0;
800;
0;
2429;
0;
600];
k = 0; % iteration counter
x_prev = ones(size(b)); % temporary x
x = ones(size(b))*2; % x array (start with 2 not 0s)
% table headings output
count = zeros(size(x));
fprintf(' k| ')
for i = 1:size(x)
count(i) = i;
fprintf('%-1c%-10s', 'x', num2str(count(i)))
end
%Calculation code
for k = 1
x_prev = x; % for checking when iteration should end
for i = 1:2 %:length(x) % row loop
%x(i) calculation loops
x(i) = b(i);
for ii = 1:length(x) % column loop
if ii ~= i % does not use column of x(i)
%%%%%%DivBy0Error%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%x(i) = x(i)-A(i,ii)*x(ii)
end
end
x(i) = x(i)/A(i,i);
end
fprintf('\n %2g|',k);
fprintf(' %-10.2e',x);
end
% end
For example the calculation for x2 would be:
x2 = (b2 +.7071*x1)/A(i,i) | A(i,i) = 0
Would my only option be to make a code to get the diagonals of the matrix to be non-zero? Or can I do something to this?

답변 (1개)

Meysam Mahooti
Meysam Mahooti 2019년 11월 29일
The Gauss–Seidel method is an iterative technique for solving a square system of n linear equations with unknown x.

카테고리

Help CenterFile Exchange에서 Operating on Diagonal Matrices에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by