Changing variable value after each loop interation and store them in array

I'm trying to store values in array xx and for each new loop iteration (i) i want the values divided by (j) to get stored in a new column (k).
My problem is that the (j) don't change for each new loop iteration and i get the same values for the entire array.
any one know how to solve this?
I want the variable 1/j in the first column to be j=0.01 and for the second column j=0.02 etc.
for i= 1:1:61
for k=1:1:8
for j=0.01:0.01:0.08
xx(i,k) = nthroot(Q(i)/((1/j)*B*(S0^(1/2))),5/3);
end
end
end
result
xx =
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.8302 0.8302 0.8302 0.8302 0.8302 0.8302 0.8302 0.8302
0.8747 0.8747 0.8747 0.8747 0.8747 0.8747 0.8747 0.8747
0.9177 0.9177 0.9177 0.9177 0.9177 0.9177 0.9177 0.9177
0.9594 0.9594 0.9594 0.9594 0.9594 0.9594 0.9594 0.9594
1.0000 1.0000 ...
Cheers!

 채택된 답변

for i=1:61
for k=1:8
xx(i,k) = nthroot(Q(i)/((100/k)*B*(S0^(1/2))),5/3);
end
end

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

제품

질문:

2016년 2월 26일

답변:

2016년 2월 26일

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