Anonymous function/ Loop

Hello,

I'm trying to solve an anonymous function with fzero but with one of the variable being a vector.

So if

     w = linspace(0,1,500);

And my anonymous function is

     anon = @(y) y*3-w*0.2;

Solving for each y when the equation is set to zero

     answer = fzero(anon,1)

But I am getting the error:

Operands to the and && operators must be convertible to logical scalar values.

Error in fzero (line 308) elseif ~isfinite(fx) ~isreal(fx)

Error in Homework (line 39) answer = fzero(anon,1)

.

My guess would be a loop, but I'm unsure how to go about it. If someone were able to help me out, I would greatly appreciate it!!

Answer 1

[Andrei Bobrov]

anon = @(y,w) y*3-w*0.2;
w = linspace(0,1,500);
answer = arrayfun(@(y)fzero(@(x)anon(x,y),1),w);

or

anon = @(y,w) y*3-w*0.2;
w = linspace(0,1,500);
answer = zeros(500,1);
for jj = 1:500
    answer(jj) = fzero(@(x)anon(x,w(jj)),1);
end

[Alyssa]

Thank you for responding! My problem is a little trickier than that though, but I tried your method and am still getting an error.

B = 4;
a = 2*pi;
sigma = 0.1;
anon = @(y,rbar) y^2*8*(2/pi)* acos(exp(-((B/2)*((1-y)/rbar))))-sigma*a*(rbar*(0.3-0.2*rbar)-y);
rbar = linspace(0,1,500);
answer = arrayfun(@(y)fzero(@(x)anon(x,y),1),rbar);

[Andrei Bobrov]

B = 4;
a = 2*pi;
sigma = 0.1;
anon = @(y,rbar) y^2*8*(2/pi)* acos(exp(-((B/2)*((1-y)/rbar))))-sigma*a*(rbar*(0.3-0.2*rbar)-y);
rbar = linspace(    eps,   1,500);
answer = arrayfun(@(y)fzero(@(x)anon(x,y),1),rbar);