how can i find same values in an array?
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I have an array a, where
a=[303.1093
94.5581
86.6591
108.1389
303.1093
107.4338
138.6919
106.8294
108.1389
149.3491
187.8940
125.0922
96.7580
303.1093
75.9192
96.2085
118.8788
303.1093
303.1093
303.1093]
then i wanna do
b=round(a);
In b I want to find the positions who are having same values and I want to mark those value as 1 and others 0.
please help me.
Thank you
-- Suchi
댓글 수: 2
Meghana Dinesh
2016년 2월 5일
편집: Meghana Dinesh
2016년 2월 5일
How much "similar"? Or do you mean "same"?
채택된 답변
Star Strider
2016년 2월 5일
편집: Star Strider
2016년 2월 5일
The unique function will obviously provide the information you want, but ‘the positions who are having similar values’ is less clear. I believe the au (unique values in ‘a’) and ‘ic’ values (the indices in ‘a’ that correspond to them) is what you want:
[au,ia,ic] = unique(round(a),'stable')
EDIT —
‘I wanna mark those same values as 1 and others 0’
I believe this does what you want:
[au,ia] = unique(round(a),'stable');
Same = ones(size(a));
Same(ia) = 0;
Result = [a Same]
Result =
303.11 0
94.558 0
86.659 0
108.14 0
303.11 1
107.43 0
138.69 0
106.83 1
108.14 1
149.35 0
187.89 0
125.09 0
96.758 0
303.11 1
75.919 0
96.209 0
118.88 0
303.11 1
303.11 1
303.11 1
-
댓글 수: 4
Star Strider
2016년 2월 5일
I wasn’t certain what you wanted. I thought you only wanted to flag the repeated values, other than the first occurrence. Since this now seems to be resolved, I’ll not pursue it further.
Stephen23
2016년 2월 5일
Good point about the "first occurrence". This did not occur to me, and the original question is ambiguous on this point.
추가 답변 (3개)
Stephen23
2016년 2월 5일
This identifies all matching rounded values, unlike the accepted answer:
b = round(a(:));
c = bsxfun(@eq,b,b.');
x = any(tril(c,-1)|triu(c,1),1);
[a(:),+x(:)]
303.1093 1
94.5581 0
86.6591 0
108.1389 1
303.1093 1
107.4338 1
138.6919 0
106.8294 1
108.1389 1
149.3491 0
187.8940 0
125.0922 0
96.7580 0
303.1093 1
75.9192 0
96.2085 0
118.8788 0
303.1093 1
303.1093 1
303.1093 1
Bhavini Sarkar
2016년 9월 17일
To find the duplicate elements of an array, first you should sort array . After sorting all duplicate elements will aggregate in adjacent positions. Now using a for loop , traverse sorted array and compare adjacent elements. If adjacent elements are equal then you found one duplicate element of array . We can also find duplicate elements of an array in linear time using some extra space.
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