What does output describe in fminbnd?
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I met some problems about 'fminbnd'. [x,fval,exitflag,output] = fminbnd(...). I don't understand when exitflag=-1, and I have no idea what happened in the output. Can anyone explain those for me? I will appreciate that.
output =
iterations: 24
funcCount: 25
algorithm: 'golden section search, parabolic interpolation'
message: [1x111 char]
답변 (2개)
Stalin Samuel
2016년 1월 12일
0 개 추천
- [x,fval,exitflag,output] = fminbnd(...) returns a structure output that contains information about the optimization in the following fields:
- algorithm 'golden section search, parabolic interpolation'
- funcCount Number of function evaluations
- iterations Number of iterations
- message Exit message *source
Stephen23
2016년 1월 12일
Why not start by reading the documentation? You can locate the documentation in 0.5 seconds using your favorite internet search engine. This is what the fminbnd documentation says:
[x,fval,exitflag] = fminbnd(...) returns a value exitflag that describes the exit condition of fminbnd:
1 fminbnd converged to a solution x based on options.TolX.
0 Maximum number of function evaluations or iterations was reached.
-1 Algorithm was terminated by the output function.
-2 Bounds are inconsistent (x1 > x2).
You can find explanations of the rest of the outputs. You might like to read it.
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Minh Handsome
2016년 1월 12일
This means that the routine was terminated before it returned a solution. This happens when the user terminates the routine via the output function. The output function is described here:
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