Matlab - symsum with itegral

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GSM
GSM 2015년 12월 11일
답변: Walter Roberson 2015년 12월 11일
Hello,
I am trying to calculate the following:
I am using the following code:
clear all;
close all
clc;
SNR0dB = 40;
SNR0 = 10 ^ (SNR0dB / 10);
LaserIntensity = 1877;
EffNoisePower = 4;
tmp_sigma = 20;
m=1;
rho=0.5;
H=1;
load coeffs
C = sqrt(SNR0*EffNoisePower) / LaserIntensity;
Zn_1 = inf;
Zn = C / 0.204;
syms k x
S1 = symsum(( ((rho*m)/(H^2*(1-rho^2)))^(m+2*k-1) ) * (1/(factorial(k)*gamma(m+k))) * integral(@(r1) r1.^(2*m+2*k+1).*exp((-r1.^2.*m)/(H^2*(1-rho^2))),Zn,Zn_1), k, 0, 10)
I get the following error:
Error using integralCalc/finalInputChecks (line 511)
Input function must return 'double' or 'single' values. Found 'sym'.
Error in integralCalc/iterateScalarValued (line 315)
finalInputChecks(x,fx);
Error in integralCalc/vadapt (line 132)
[q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 83)
[q,errbnd] = vadapt(@AToInfInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in SumOverIntegral (line 21)
S1 = symsum(( ((rho*m)/(H^2*(1-rho^2)))^(m+2*k-1) ) * (1/(factorial(k)*gamma(m+k))) * integral(@(r1)
r1.^(2*m+2*k+1).*exp((-r1.^2.*m)/(H^2*(1-rho^2))),Zn,Zn_1), k, 0, 10)
Can someone please help how to overcome the error of sending symbol to the integral function?
Thank you.

채택된 답변

Walter Roberson
Walter Roberson 2015년 12월 11일
Do not use integral() for symbolic expressions: use int()

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