Function to take grid reference

fairly new to this, would any body be able to tell me how i can create a function that can take a grid reference eg A10, C4, F6, etc and convert it into a row and column index? oh btw the grid has to be ten by ten!

Answer 1

[Stephen23]

>> fun = @(s)[upper(s(1))-64,str2num(s(2:end))];
>> fun('A10')
ans =
    1   10
>> fun('C4')
ans =
   3   4
>> fun('F6')
ans =
   6   6

[Stephen23]

Try this:

S = input('Enter the grid reference you wish to convert: ','s');
C = upper(S(1))-64
R = str2num(s(2:end))

Answer 2

[Walter Roberson]

Under the condition that it is 10 by 10 exactly,

   r1 = GR(1) - 'A' + 1;
   if length(GR) == 2
     r2 = GR(2) - '0';
   else
     r2 = 10;
   end

You do not specify whether the letters indicate rows or columns so make the appropriate choice [r1,r2] or [r2,r1]

If the grid can be larger than 10 x 10 then the "else" would have to be adjusted. If the grid can be larger than 26 then the r1 logic would need to be adjusted.

[Walter Roberson]

Note: Stephen's code is more compact; my code is more efficient for the particular requirements that were given.

[keyboard_cuts]

Thanks for your response, its much appreciated however like i said im new to this so im still a little unsure. My code now looks like

 my_grid= zeros(10,10); %creates the matrix
GR=input('Enter the grid reference you wish to convert')%takes in input

r1 = GR(1) - 'A' + 1 if length(GR) == 2 r2 = GR(2) - '0' else r2 = 10 end however it still does not give me an output answer ie A1 =1,1 or C8= 3,8 or what have you