replacing a number

I have a value D=[1 20]

another value F=[1 3 4 5 6 7 8 ]

no i want to compare two values D and F if value of F is not present in D in should be added to d1 ,i need a for loop.please help

Answer 1

[Andrei Bobrov]

setdiff(F,D)

ADD [13:44(UTC+4) 10.01.2012]

e.g. for every row of array F:

>> D = [1    20];
>> F =[1     3     4     5     6     7     8;
     9    10    11    20    16    1    18];
>> out = arrayfun(@(i1)setdiff(F(i1,:),D),1:size(F,1),'un',0)
out = 
    [1x6 double]    [1x5 double]
>> out{:}
ans =
     3     4     5     6     7     8
ans =
     9    10    11    16    18
>>

[FIR]

andrei can u tell how to process this please ,struck here for long

http://www.sendspace.com/file/scymbl

[FIR]

andrei ur equation returns error for value F having more than 1 column

??? Error using ==> setdiff at 51

A and B must be vectors or 'rows' must be specified.

Error in ==> new at 81

D1=setdiff(F,D)

[Andrei Bobrov]

setdiff(F(:),D)

[FIR]

thanks andrei can u answer to my other question which i posted

[FIR]

andrei i get answer for 1column but not for other columns