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How do I use while loop to cycle through 3 cases and stop after evaluating the three cases?
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My homework problem reads:
"A mathematical relationship between x and y is described by the following expressions:
y=A*exp(x^2)-B*x^3+x-1 if x<=0 (Case 1)
y=A*log10(x)-B*x^4+1.5 if 0<x<=10 (Case 2)
y=A/log(x)-B/x+C if x>10 (Case 3)
where A, B, and C are constants. Write a program that inputs the constants A,B,C, and the argument x, and computes the corresponding value of y. Print x by using 4 decimal places, and y by using 5 decimal places.
Use if/else statements to choose the proper expression for y, corresponding to selected x.
After reading A,B,C, your program should use a while loop to evaluate y for scanned x in each of the above three cases. If you input x from the same interval again, your program should ask you to input x from another interval, until you input x once from each interval.
Your output should look like:
Enter A, B, C:
-1.5 2.5 0.125
Enter x: -3.5
Case 1
x value is = -3.5000 and y value is = -313369.24580
Enter x: -5
Enter x from another interval!
Enter x: 1.85
Case 2
x value is = 1.8500 and y value is = -28.18452
Enter x: 12
Case 3
x value is = 12.0000 and y value is = -0.68698"
So far i have the if/else conditions down but i'm not sure how to proceed with the while loop. any guidance will be appreciated!
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답변 (1개)
Stalin Samuel
2015년 11월 18일
A = -1.5;B = 2.5; C= 0.125;
count=[1 1 1]%three one for three cases
while(sum(count)>0)
x = input('enter the value of x:');
if x<=0
if count(1)>0
count(1) = 0;%fisrt case tested
y=A*exp(x^2)-B*x^3+x-1
else
disp('enter another no')
end
elseif x>0&x<=10
if count(2)>0
count(2) = 0; %second case tested
y=A*log10(x)-B*x^4+1.5
else
disp('enter another no')
end
elseif x>10
if count(3)>0
count(3) = 0;%third case tested
y=A/log(x)-B/x+C
else
disp('enter another no')
end
end
end
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