problem with gradient- index exceeds matrix dimensions.

Does anyone know what is the problem with the following code? Many thanks.
>> ss=[ 1 9 19 31 45 61 79 99 121 145]; >> t2 = gradient(ss)
and I received error message below: "Index exceeds matrix dimensions."
I checked matlab help file, it says: FX = gradient(F), where F is a vector, returns the one-dimensional numerical gradient of F. Here FX corresponds to ∂F/∂x, the differences in x (horizontal) direction.
So I don't understand why it is not working now.

답변 (2개)

Guillaume
Guillaume 2015년 11월 6일

1 개 추천

Most likely you have a variable called gradient, so instead of calling the function gradient you're indexing into the variable. Since the variable has less than 145 elements, you get 'index exceeds matrix dimension'
Don't use matlab function names as variable names.

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Use
which gradient
just before gradient(ss) to see what gradient actually is.

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June
June 2015년 11월 6일

0 개 추천

Thanks for reminding me. Yes, I am testing someone else's code.

카테고리

도움말 센터File Exchange에서 Matrix Indexing에 대해 자세히 알아보기

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2015년 11월 6일

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2015년 11월 6일

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