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조회 수: 2 (최근 30일)
mohamed  al-asklany
mohamed al-asklany 2012년 1월 5일
in butter(1,wn) i know wn is normal frequency =(cut off/nyq.freq) in amplitude modulation what will be wn=? if carrier freq=fc and i calulat 0:.001:1 sample and message freq fm

채택된 답변

Rick Rosson
Rick Rosson 2012년 1월 6일
Code:
dt = 0.001; % sampling time (seconds per sample)
Fs = 1/dt; % sampling rate (samples per second)
Fnyq = Fs/2; % Nyquist frequency (hertz)
Fco = fm + bw; % Cut-off frequency (hertz)
wn = Fco/Fnyq; % Normalized cut-off (dimensionless)
Explanation:
  • dt is the sampling time (in seconds per sample)
  • Fs is the sampling rate (in samples per second)
  • Fnyq is the Nyquist frequency (in hertz)
  • Fco is the cutoff frequency (in hertz)
  • bw = bandwidth (in hertz)
  • Fc is not needed to compute wn
You should make sure that the following conditions are true:
bw << fm << fc
and
bw << fm << Fs
HTH.
Rick
  댓글 수: 1
mohamed  al-asklany
mohamed al-asklany 2012년 1월 7일
excellent ,now if i have a message like cos(2*pi*fm*t), and i want to build function which make frequency modulation
for this message it does not work and if it work(some times) the receiver can not be bone my problem is to how to make discriminator and how to put the message in frequency and how to see spectrum of signal and somthing else i add to am signal a noise (awgn) is this code correct
snr=10^(snr/10);
vn=var(tx)/snr; %AWGN channl
n=sqrt(vn)*randn(1,1001);
tx=tx+n;
assuming t=0:.001:1
and tx is the transmitted signal

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추가 답변 (1개)

Rick Rosson
Rick Rosson 2012년 1월 5일
Please try:
dt = 0.001;
Fs = 1/dt;
Fnyq = Fs/2;
Fco = fm + bw;
wn = Fco/Fnyq;
HTH.
  댓글 수: 6
Rick Rosson
Rick Rosson 2012년 1월 6일
The idea of bandwidth is that the message has a spectrum that extends across a range of frequencies centered at f = fm. You can assume that the range is [ fm-bw ... fm+bw ].
Rick Rosson
Rick Rosson 2012년 1월 6일
You should also make sure that the following conditions are true:
bw << fm
and
fm << fc

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