Should the max function and the fminbnd function produce the same result? Also, is there something wrong with my MATLAB syntax?

this is my code guys. my height.m file is: function [h] = height(t)

h = @(t) ((-9.8).*(2.^(-1))).*(t.^2) + 125.*t + 500;

%h(h<0) = 0; %I DON'T UNDERSTAND WHY THIS DOESN'T WORK. if h(t) <0 h=0 end end

My actual program is: %Part A clear all; clc; t = 0:.01:30; h = height(t); %the h(h<0) is acting weird

%Part C (maxima)---I swapped the order for the plotting %max function [xpsudeomax,ymax] = max(h(t)); xrealmax = t(ymax); maxfunction = [xrealmax,ymax] %THIS IS LESS ACCURATE THAN THE BELOW VERSION-WHY?

%fminbnd function [xmax2,ymaxpsudeo]= fminbnd(@(t) (-1.*h(t)),0,30); yrealmax = -1.*ymaxpsudeo; format long g fminbndmax = [xmax2,yrealmax] %Is fminbnd and max function suppposed to give the %exact same answer? %THIS IS THE ACCURATE ONE-WHY?

Answer 1

[John D'Errico]

NO. max is not an optimization tool. It just finds the maximum element of an array. VERY different.

Anyway, fminbnd is a MINIMIZER.

Finally, as you have written it, h is a function handle. You cannot then do a vectorized array operation on it, like this:

h(h<0) = 0;

[Ruten9]

how would I deal with the h problem? Would i write it like h(h(t)<0)=0 ?