[x,fs,nbits] = wavread('w.wav');
%sound(x,fs);
h = zeros(1,4000);
h(1) = 1;
h(1000) = 0.25;
h(2000) = (1/16);
h(3000) = 1/64;
h(4000) = 1/256;
y = conv(x,h);
y = y/max(y);
sound(y,fs);
it gives me an error "A and B must be vectors" as for y = conv(x,h) .

답변 (2개)

Star Strider
Star Strider 2015년 9월 29일

1 개 추천

Check the size of ‘x’. It may be a two-column matrix (one column for each channel).

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ayman daraghmah
ayman daraghmah 2015년 9월 29일
yes it's two-column matrix. Do i need to use 2D convolution ?
Star Strider
Star Strider 2015년 9월 29일
Not strictly 2D but do the same convolution on both channels, or if the same sound is duplicated in both channels, just one column of ‘x’ with your current code.
You could do one 2D convolution or 2 1-D covolutions
rightChannel = x(:, 1);
echoRight = conv(rightChannel, h, 'same');
leftChannel = x(:, 2);
echoLeft = conv(leftChannel , h, 'same');
% Combine
newSignal = [echoRight, echoLeft];
or something like that.

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Image Analyst
Image Analyst 2015년 9월 29일

0 개 추천

Maybe try
y = conv2(x, [h,h], 'same');
or
y = conv2(x,[h;h], 'same');
so you're doing a 2D convolution

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2015년 9월 29일

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2015년 9월 29일

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