Using a matrix where every column has a different number of rows, to obtain a matrix with the exact same dimensions for every column.

for n=1:42;
    Lx(max(size(L(1:end,n))))=L(1:end,n).*[sind(theta{n,1}(1:end,1))];
end.

L is a matrix with 42 columns, but every column has a different number of rows. Lx will have the exact same dimensions for every column, it is merely L times the cos of various angles. How can i notate this to produce what i want? should i convert L into a 1x42 array? Also, theta is {42,1} but every element of theta has a one column but different number of rows. this is quite messy i know. thanks!

Answer 1

[Walter Roberson]

Use cell arrays if you need a different number of elements per column (or row).

[Andrew Wiebe]

How do i change L into a cell array?

[Walter Roberson]

What form is your data in now? It cannot be a numeric array, as numeric arrays always have the same number of rows per column.