필터 지우기
필터 지우기

If loop using cell arrays

조회 수: 7 (최근 30일)
Bas
Bas 2015년 9월 14일
댓글: Titus Edelhofer 2015년 9월 14일
Hi,
I have 2 matrices:
A with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) defining salaries
B with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) contains either a 0 or a 1
And last I have 2 boundary values C= 2600 and D= 1700.
I want to check the following:
if B(each value) == 0 && A(each value) > C
A(this value)= C
elseif B(each value) == 1 && A(each value) > D
A(this value)= D
end
Can anyone help me out?
  댓글 수: 1
Walter Roberson
Walter Roberson 2015년 9월 14일
There is no such thing as an "if loop". There are "for loop" and there are "while loop" and there are "if statement". A loop would have to execute its body multiple times, but "if" executes the body only 1 time or 0 times.

댓글을 달려면 로그인하십시오.

채택된 답변

Guillaume
Guillaume 2015년 9월 14일
You don't need any if. Just use logical operations. Your first condition is to replace elements when B is false (i.e. B==0 or simply ~B) and A greater than C, so is simply writen as A(~B & A>C). Similarly your second condition is simply A(B==1 & A>D) (which simplifies to A(B & A>D). You just have to apply that to each cell of the cell arrays:
for cellidx = 1:numel(A)
a = A{cellidx};
b = B{cellidx};
a(~b & a>C) = C;
a(b & a>D) = D;
A{celldix} = a;
end
  댓글 수: 1
Bas
Bas 2015년 9월 14일
Thanks Guillaume, this is what I was searching for!

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Titus Edelhofer
Titus Edelhofer 2015년 9월 14일
Hi,
I'm not 100% sure I understand what you want to do, but I guess it should be like this
for i=1:length(A)
if all(B{i}(:)==0 & A{i}(:)>C)
A{i}(:) = C;
elseif all(B{i}(:)==1 & A{i}(:)>D)
A{i}(:) = D;
end
end
Titus
  댓글 수: 4
Guillaume
Guillaume 2015년 9월 14일
편집: Guillaume 2015년 9월 14일
Both codes have the following preconditions:
assert(isequal(numel(A), numel(B)));
assert(all(cellfun(@(a,b) isequal(size(a), size(b)), A, B)));
Titus Edelhofer
Titus Edelhofer 2015년 9월 14일
I wish I could vote for a comment! Nice assert calls.

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Logical에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by