How to define the value of "t" from function f(t)
조회 수: 18 (최근 30일)
이전 댓글 표시
Hello,
I have a function
f(t)=exp(-0.01*t.^2).*cos(2.*t)
where 't' is a function handle (f=@t)
I need to define 't' when f(t)=0.4.
How do I do this?
Sergey
댓글 수: 0
채택된 답변
Walter Roberson
2015년 9월 9일
It sounds to me like you might be attempting to solve exp(-0.01*t.^2).*cos(2.*t) to find the t where the expression becomes 0.4 . If so then there are an infinite number of solutions. You can find one of them by using
syms f(t)
f(t) = exp(-0.01*t.^2).*cos(2.*t);
vpasolve(f(t)=0.4)
댓글 수: 2
Steven Lord
2015년 9월 9일
Or if you don't have Symbolic Math Toolbox, you could use FZERO from MATLAB. Rewrite your expression so it's in the form g(t) = 0:
f = @(t) exp(-0.01*t.^2).*cos(2.*t);
g = @(t) f(t)-0.4; % Transforming f(t) = 0.4 -> f(t)-0.4 = 0
Then call FZERO to find a zero of g(t). Change the initial guess to locate additional zeros.
fzero(g, 0)
추가 답변 (0개)
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!