ind2sub output dimension

My question is regarding the output of the ind2sub function. In my code, since the input dimention of ind2sub changes, i should expect the output dimention to change. But a code like this is not working.

B = rand(6,6,6);
A(1:ndims(B)) = ind2sub(size(B),56);

The output of the above code is [56 56 56] while I'm expecting something like [2 4 2].

Any suggestion?

Answer 1

[Fangjun Jiang]

Follow the same clue in the answer to your other question, you can do the following:

B=rand(4,5,6);
Ind=(20:25).';

n=ndims(B);
Sub=cell(1,n);
[Sub{:}]=ind2sub(size(B),Ind)
SubMatrix=cell2mat(Sub)

Sub = 
    [6x1 double]    [6x1 double]    [6x1 double]
SubMatrix =
     4     5     1
     1     1     2
     2     1     2
     3     1     2
     4     1     2
     1     2     2

[Mohsen Davarynejad]

Thanks.

Answer 2

[bym]

you need multiple assignments for that function.

    [r,c,p]=ind2sub(size(B),56)

r =

       2

c =

       4

p =

       2

[Paulo Silva]

that one was bugging me for some time, +1 vote

[Mohsen Davarynejad]

But as I've mentioned, the output dimention is changing. So I do not know if the I need three variables, in your case r, c, p, of if I need more.