How to pick a value according to its probability
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Hi,
Let's say
P = [0.1 0.3 0.4 0.2]
X = [1 2 5 9]
where P(n) is the probability to select the X(n) element. I wish to make a function that select a "random" element of X according to its probability, like
f = myfun(P,X)
>> f = 2 (occurs around 30%)
thx a lot
댓글 수: 4
채택된 답변
Sean de Wolski
2011년 12월 7일
f = X(find(rand<cumsum(P),1,'first'))
댓글 수: 1
Walter Roberson
2011년 12월 7일
The answers in the other thread took care in case cumsum(P) < 1 as can happen due to round-off error.
추가 답변 (3개)
Jonathan
2018년 9월 3일
편집: Jonathan
2018년 9월 3일
The accepted answer is not doing any sanity check, and is sensitive to rounding errors. You should use randsample instead.
To sample n points from X, with replacement, and probabilities P:
randsample( X, n, true, P )
This can also be used with a custom RandStream (see documentation). Be aware that this function does NOT check for negative values in P; check manually if needed.
댓글 수: 4
Steven Lord
2020년 4월 16일
You can use discretize (which didn't exist when this question was asked originally) to do this. Generate uniform random numbers, bin them using bins whose widths are given by P, and for each bin return the corresponding element of X.
P = [0.1 0.3 0.4 0.2];
X = [1 2 5 9];
values = discretize(rand(1, 1e4), cumsum([0 P]), X);
histogram(values, 'Normalization', 'probability')
The probabilities shown in the histogram should agree pretty closely with the values in P.
댓글 수: 0
Mendi
2021년 7월 9일
The fastest one (100ns-200ns):
function [idx] = get_random_choice(p)
% Random choice with probability
% Example: get_random_choice([0.2,0.7,0.1])
N=length(p); idx=1; cump=0;
r=rand;
while(idx<N)
cump=cump+p(idx);
if(cump>r),break,else,idx=idx+1;end
end
end
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