How to find the equation of a graph after getting Xdata and Ydata ?

조회 수: 1 (최근 30일)
Joel Sande
Joel Sande 2015년 8월 7일
댓글: Joel Sande 2016년 4월 18일
x = [0 1 2 3 4 5 6 7 8 9 10];
y = [4 3 4 7 12 19 28 39 52 67 84];
% How to find the function y = F(x) ??
% because I need for example to know
% if x = 1.5
% y = ??
% the solution should be something regarding regression.

채택된 답변

Azzi Abdelmalek
Azzi Abdelmalek 2015년 8월 7일
편집: Azzi Abdelmalek 2015년 8월 7일
You can find yi by interpolation
x = [0 1 2 3 4 5 6 7 8 9 10];
y = [4 3 4 7 12 19 28 39 52 67 84];
xi= 1.5
yi=interp1(x,y,xi)

추가 답변 (2개)

Brendan Hamm
Brendan Hamm 2015년 8월 7일
The easiest way would be to use the polynomial fitting functions. For this you need to know what order polynomial to fit, so visualize the data:
plot(x,y)
The data you gave looks quadratic, so let's find the coefficients for a second order polynomial:
coeff = polyfit(x,y,2);
Now evaluate the polynomial at a new value of x:
xNew = 1.5;
yNew = polyval(coeff,xNew);
plot(xNew,yNew,'r*');
  댓글 수: 5
Joel Sande
Joel Sande 2015년 8월 11일
Thanks for the advice.
Joel Sande
Joel Sande 2016년 4월 18일
Yes, Finally I used Polyfit

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Walter Roberson
Walter Roberson 2015년 8월 7일
one of the infinite number of solutions is:
x = [0 1 2 3 4 5 6 7 8 9 10];
y = [4 3 4 7 12 19 28 39 52 67 84];
pp = polyfit(x, y, length(x)-1);
y1_5 = polyval(pp, 1.5)
Another of the infinite solutions is:
x = [0 1 2 3 4 5 6 7 8 9 10];
y = [4 3 4 7 12 19 28 39 52 67 84];
y1_5 = 19;
It is not mathematically possible to distinguish between these two solutions as to which one is "more correct".
  댓글 수: 2
Joel Sande
Joel Sande 2016년 4월 18일
It is exactelly what I used, because I didn t know the order of the polynom.

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