The command normrnd times a scalar
조회 수: 1 (최근 30일)
이전 댓글 표시
Hi,
I would like to know how Matlab understands the following:
eta=normrnd(0,sigma)/100
Is this command going to re-scale eta by 100 or multiply the normrnd(0,sigma) by 1/100 and therefore the variance is (sigma/100)^(2)
Can somone clarify this point for me ?
Many thanks
댓글 수: 0
답변 (1개)
Walter Roberson
2015년 7월 12일
It is going to multiply by 1/100.
댓글 수: 4
Walter Roberson
2015년 7월 12일
normrnd is randn() * sigma + mu. Your mu is 0, so your normrnd() calls are randn() * sigma . It then does not matter if you pass sigma/100 or if you divide the result of the normrnd() by 100.
If the mu was not 0 then the two situations would not be the same.
참고 항목
카테고리
Help Center 및 File Exchange에서 Random Number Generation에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!