Given a named function, how can I call this function, and not the subfunction of the same name?

조회 수: 2 (최근 30일)
My function is passed the name of a function (as a string). It just so happens that my function contains a subfunction of that name. I want to make sure I call the external function, instead of the subfunction. How can I achieve this?
E.g. save the following in test.m:
function test
feval(evalin('base', 'str2func(''help'')'), 'help');
function varargout = help(varargin)
error('Should not get here!');
[varargout{1:nargout}] = deal([]);
Then calling test gives:
>> test
Error using test>help (line 6)
Should not get here!
Error in test (line 2)
feval(evalin('base', 'str2func(''help'')'), 'help');
  댓글 수: 1
Oliver Woodford
Oliver Woodford 2015년 5월 29일
I would say what I'm seeing is unexpected behaviour. Also, putting
evalin('base', 'which(''help'')')
as the first line in the help subfunction gives:
C:\....\test.m (help) % Subfunction of test
which is unexpected too.

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채택된 답변

Titus Edelhofer
Titus Edelhofer 2015년 5월 29일
what about this:
feval(evalin('base', '@(x) help(x)'), 'help')
This works fine. And as you noted yourself, using {:} you can expand the input variable as cell array.

추가 답변 (2개)

Philip Borghesani
Philip Borghesani 2015년 5월 29일
편집: Philip Borghesani 2015년 5월 29일
There is a much simpler solution to this:
function fh=test
fh=str2func('@(x) help(x)');
str2func isolates any anonymous function created from the surrounding environment see Loren's Blog
  댓글 수: 1
Oliver Woodford
Oliver Woodford 2015년 5월 30일
Nice! Thanks, Phil. I find it bizarre that str2func finds a different function depending on whether you use the anonymous function syntax or just the function name, though.

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Titus Edelhofer
Titus Edelhofer 2015년 5월 29일
Hi Oliver,
although this is not an answer to your question it might help anyway: this is one of the reasons to use function handles instead of strings denoting functions. The big advantage of a function handle is, that the function is determined in the moment the function handle in contrast to strings, where in the moment of evaluation the dispatching happens.
If you pass @help instead of 'help' to your function as input, you are sure, that the correct function is used.
  댓글 수: 5
Oliver Woodford
Oliver Woodford 2015년 5월 29일
편집: Oliver Woodford 2015년 5월 29일
The unlikely function name thing is a workaround which I can use. I'm hoping I won't need to, though. I can use the solution above :). Although the number of input arguments aren't known, I can put them in a cell array:
feval(evalin('base', '@(x) help(x{:})'), {'help'})
If you make it an answer I'll accept it.
Alfonso Nieto-Castanon
Alfonso Nieto-Castanon 2015년 5월 29일
편집: Alfonso Nieto-Castanon 2015년 5월 29일
couldn't you use:
feval(evalin('base','@(varargin) help(varargin{:})'),'help')
to account for variable number of inputs?

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