How do I find the duration of a number in an array?
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Given the array
c=[3 3 3 5 5 6 7 8 1 1 3 3 3 0 0 0 4 4 4 5 6 7 8 3 3 3 9 10 3];
I am trying to find the average duration of each number in this array. For example, I am looking to find the average duration for 3 in this array. I know that 3 occurs 10 times but is grouped into 4 separate occurrences. I want the output to be the average duration for 3...which is 2.5. please help!
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채택된 답변
Andrei Bobrov
2015년 5월 28일
편집: Andrei Bobrov
2015년 5월 28일
c = c(:);
ii = [true;diff(c)~=0];
i2 = diff([find(ii);numel(ii)+1]);
[a,b,c0] = unique(c(ii),'first'); % in new version of MATLAB:
[~,jj] = sort(b); %
[~,j1] = sort(jj); % [a1,~,c1] = unique(c(ii),'stable');
a1 = a(jj); %
c1 = j1(c0); %
out = [a1,accumarray(c1,i2,[],@mean)];
or with sorting
ii = [true;diff(c)~=0];
i2 = diff([find(ii);numel(ii)+1]);
[a,~,c0] = unique(c(ii));
out1 = [a,accumarray(c0,i2,[],@mean)]
추가 답변 (1개)
Azzi Abdelmalek
2015년 5월 28일
c=[3 3 3 5 5 6 7 8 1 1 3 3 3 0 0 0 4 4 4 5 6 7 8 3 3 3 9 10 3];
[ii,jj,kk]=unique(c)
d=accumarray(kk,1)
for k=1:numel(ii)
a=ii(k)
res(k)=d(k)/numel(strfind([0 c==a 0],[0,1]))'
end
out=[ii' res']
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