monte carlo simulation

can anyone please help me figure out whats wrong with this code. im trying to run a simulation where 3 people flip a coin if all are heads or tais they take them back. however if two coins come up heads or tails the person with the unique coin wins a coin from the other two. my problem is that my code doesnt follow the given conditions based on the code and instead seems to excute only one of the statements instead of following the given conditions

a=5; % person 1 int coin

b=5; % person 2 int coin

c=5; % person 3 int coin

step=0

     for i=1:1:100

         step=step+1

      d=rand(1,3) % coin flip for 3 people 

      if d(1,1)&&d(1,2) < .5            
          a= a -1
          b= b-1
          c= c+2

      elseif d(1,1)&&d(1,2) >.5
        a= a -1
          b= b-1
          c= c+2

      elseif d(1,1)&&d(1,3) < .5

          a= a -1
          b= b+2
          c= c-1

      elseif d(1,1)&&d(1,3) >.5
        a= a -1
          b= b+2
          c= c-1

      elseif d(1,3)&&d(1,2) < .5
          a= a +2
          b= b-1
          c= c-1

      elseif d(1,2)&&d(1,3) >.5
        a= a +2
          b= b-1
          c= c-1

      elseif d(1,1)&&d(1,2)&&d(1,3) >.5
          a=a+0
          b=b+0
          c=c+0

      elseif d(1,1)&&d(1,2)&&d(1,3) <.5
          a=a+0
          b=b+0
          c=c+0
      end
     end

disp(d(1,1))
disp(d(1,2))
disp(d(1,3))

Answer 1

[Titus Edelhofer]

Hi Raymond,

your inequality conditions must be done each by itself: replace

if d(1,1)&&d(1,2)<.5

by

if d(1,1)<0.5 && d(1,2)<0.5

and likewise for the others. What you wrote is essentially

if d(1,1)~=0 && d(1,2)<.5

which is more or less the same as d(1,2)<0.5 since rand very seldom hits exactly zero.

Titus