parfeval evaluation is slow

조회 수: 4 (최근 30일)
Poul-Erik Hansen
Poul-Erik Hansen 2025년 4월 11일
댓글: Walter Roberson 2025년 4월 15일
Hi
I am using parfeval to calculate the eigenvalues of a matrix M with typical dimension of 1500x1500x100. The parfeval evaluations is slow since I read the output just after the evaluation of each matrix M(:,:,k) k=1,..,100. I want to store all the eigenvalues and eigenvectores in the variabel f and read the output after finishing the parfeval evaluation.
Current code:
eigMtr=complex(zeros(2*L,2*NumOfSlabs*L));
W=eigMtr;
W_1=complex(zeros(L,2*NumOfSlabs*L));W_2=W_1;
for k=1:NumOfSlabs
f=parfeval(@eig,3,M(:,:,k));
[Wt,Dt] = fetchOutputs(f);
start=1+(k-1)*2*L;stop=2*k*L;
eigMtr(1:2*L,start:stop)=sqrt(Dt);
W1=Wt(1:L,:);
W2=Wt(L+1:2*L,:);
W_1(:,start:stop)=W1;
W_2(:,start:stop)=W2;
W(1:L,start:stop)=W2;
W(L+1:2*L,start:stop)=W1;
end
I want to do something like this
for k=1:NumOfSlabs
f=parfeval(@eig,3,M(:,:,k));
end
for k=1:NumOfSlabs
[idx,Wt,Dt] = fetchNext(f)
start=1+(k-1)*2*L;stop=2*k*L;
eigMtr(1:2*L,start:stop)=sqrt(Dt);
W1=Wt(1:L,:);
W2=Wt(L+1:2*L,:);
W_1(:,start:stop)=W1;
W_2(:,start:stop)=W2;
W(1:L,start:stop)=W2;
W(L+1:2*L,start:stop)=W1;
end
Thanks for your help
Poul-Erik

채택된 답변

Walter Roberson
Walter Roberson 2025년 4월 11일
Note the correction to the number of output arguements parameter in the parfeval() call
f = cell(NumOfSlabs, 1);
for k=1:NumOfSlabs
f{k} = parfeval(@eig,2,M(:,:,k));
end
wait(f{1});
for k=1:NumOfSlabs
[Wt,Dt] = fetchOutputs(f{k});
start=1+(k-1)*2*L; stop=2*k*L;
eigMtr(1:2*L,start:stop)=sqrt(Dt);
W1=Wt(1:L,:);
W2=Wt(L+1:2*L,:);
W_1(:,start:stop)=W1;
W_2(:,start:stop)=W2;
W(1:L,start:stop)=W2;
W(L+1:2*L,start:stop)=W1;
end
  댓글 수: 8
Edric Ellis
Edric Ellis 2025년 4월 15일
Ah, actually, the Parallel Computing Toolbox page for parfeval already does have examples showing arrays https://uk.mathworks.com/help/parallel-computing/parallel.pool.parfeval.html . @Walter Roberson were you looking at the page in the MATLAB doc? https://uk.mathworks.com/help/matlab/ref/parfeval.html .
Walter Roberson
Walter Roberson 2025년 4월 15일

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Steven Lord
Steven Lord 2025년 4월 11일
Have you compared the time of your parfeval call to the time required for a call to the pageeig function?
  댓글 수: 1
Poul-Erik Hansen
Poul-Erik Hansen 2025년 4월 12일
Yes, the two functions have similar speed but different cpuload.
pageeig cpu load 50%
parfeval cpuload 100 %

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

제품


릴리스

R2024b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by