The size of the indicated variable
이전 댓글 표시
Hi,
When I run the following code ;
i=0;
t0 = clock;
while etime(clock, t0) < 10
disp(clock);
pwm(i)=0;
i = i +1;
tic
while toc<secs
end
pwm(i)=1;
i = i +1;
tic
while toc<secs
end
end
I get the following warning ;
The size of the indicated variable or array appears to be changing with each loop iteration. Commonly, this message appears because an array is growing by assignment or concatenation.
and application hangs even if it's a very simple algorithm.
Any ideas ?
답변 (3개)
Image Analyst
2011년 11월 20일
I don't know how big pwm might get. Maybe run it once to see. Let's say that it ends up being 100000 elements long. Then, before your while loop, you simply preallocate:
pwm = zeros(1, 100000);
댓글 수: 3
Yigit
2011년 11월 20일
Image Analyst
2011년 11월 21일
I can't run your code because secs is undefined. What value are you using for it?
Yigit
2011년 11월 22일
Kostas
2011년 11월 20일
0 개 추천
Is there any chance the variable secs to have such a little value that it is always litter than "toc"? In such a case your code goes into an infinite loop which cause it to hang.
Jan
2011년 11월 21일
0 개 추천
The code fails, because you try to access "pwm(i)" for i=0, but the index must be >= 1. When I start with "i=1;" the code runs successfully on my computer.
Where does the program fail on your computer? You can eitehr use the debugger or insert some disp command to check this.
I would avoid "tic; while toc<secs, end". A pause command would be smarter.
카테고리
도움말 센터 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!