How combine line with contour plot?

i try to solve the problem i did but in graph i have some problem i did for 1 line by maple but i can't do it for two line and three line in maple althogh i think this kind of plot is taken from matlab can any one do this kind of graph

for the one line the shape of contour is

 u(x, y, t) == 0.16e2 * (-5 * y - 8 * t + 5 * x) / (-(96 * y ^ 2) - (64 * t * y) - 0.64e2 * (t - x / 0.2e1) * y - 0.64e2 * (t - x / 0.2e1) ^ 2 - 0.75e2 - (16 * t ^ 2) - (16 * t * (-y - 2 * t + x)) - (4 * (-y - 2 * t + x) ^ 2))

and the line is

 y == -x / 0.3e1 - sqrt(0.3e1) * sqrt(0.5e1) / 0.6e1;

for the 2 line and 6 shape of countour in fig2 d we have

 u(x, y, t) == -2 * ((0.7933424e7 / 0.1891125e7+0.36508832e8 / 0.1891125e7*i) * ((-1-2*i) * t + (3-4*i) * y + t + (1+2*i) * x) + (0.8059833e7 / 0.1092650e7+0.84073113e8 / 0.2185300e7*i) * ((-0.2e1 / 0.3e1-i) * t + (0.5e1 / 0.9e1-0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1+i) * x) + (0.7933424e7 / 0.1891125e7-0.36508832e8 / 0.1891125e7*i) * ((-1+2*i) * t + (3+4*i) * y + t + (1-2*i) * x) + (0.6e1 / 0.65e2-0.9e1 / 0.65e2*i) * ((-1-2*i) * t + (3-4*i) * y + t + (1+2*i) * x) * ((-0.2e1 / 0.3e1-i) * t + (0.5e1 / 0.9e1-0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1+i) * x) * ((-1+2*i) * t + (3+4*i) * y + t + (1-2*i) * x) + (0.8059833e7 / 0.1092650e7-0.84073113e8 / 0.2185300e7*i) * ((-0.2e1 / 0.3e1+i) * t + (0.5e1 / 0.9e1+0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1-i) * x) + (0.9e1 / 0.65e2-0.18e2 / 0.65e2*i) * ((-1-2*i) * t + (3-4*i) * y + t + (1+2*i) * x) * ((-0.2e1 / 0.3e1-i) * t + (0.5e1 / 0.9e1-0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1+i) * x) * ((-0.2e1 / 0.3e1+i) * t + (0.5e1 / 0.9e1+0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1-i) * x) + (0.6e1 / 0.65e2+0.9e1 / 0.65e2*i) * ((-1-2*i) * t + (3-4*i) * y + t + (1+2*i) * x) * ((-1+2*i) * t + (3+4*i) * y + t + (1-2*i) * x) * ((-0.2e1 / 0.3e1+i) * t + (0.5e1 / 0.9e1+0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1-i) * x) + (0.9e1 / 0.65e2+0.18e2 / 0.65e2*i) * ((-0.2e1 / 0.3e1-i) * t + (0.5e1 / 0.9e1-0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1+i) * x) * ((-1+2*i) * t + (3+4*i) * y + t + (1-2*i) * x) * ((-0.2e1 / 0.3e1+i) * t + (0.5e1 / 0.9e1+0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1-i) * x)) / ((0.9e1 / 0.65e2) * ((-1-2*i) * t + (3-4*i) * y + t + (1+2*i) * x) * ((-0.2e1 / 0.3e1-i) * t + (0.5e1 / 0.9e1-0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1+i) * x) * ((-1+2*i) * t + (3+4*i) * y + t + (1-2*i) * x) * ((-0.2e1 / 0.3e1+i) * t + (0.5e1 / 0.9e1+0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1-i) * x) + (0.27783e5 / 0.1625e4-0.11619e5 / 0.1625e4*i) * ((-1+2*i) * t + (3+4*i) * y + t + (1-2*i) * x) * ((-0.2e1 / 0.3e1+i) * t + (0.5e1 / 0.9e1+0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1-i) * x) + (0.135e3 / 0.52e2) * ((-0.2e1 / 0.3e1-i) * t + (0.5e1 / 0.9e1-0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1+i) * x) * ((-0.2e1 / 0.3e1+i) * t + (0.5e1 / 0.9e1+0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1-i) * x) + (0.74331e5 / 0.109265e6+0.118467e6 / 0.109265e6*i) * ((-0.2e1 / 0.3e1-i) * t + (0.5e1 / 0.9e1-0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1+i) * x) * ((-1+2*i) * t + (3+4*i) * y + t + (1-2*i) * x) + (0.74331e5 / 0.109265e6-0.118467e6 / 0.109265e6*i) * ((-1-2*i) * t + (3-4*i) * y + t + (1+2*i) * x) * ((-0.2e1 / 0.3e1+i) * t + (0.5e1 / 0.9e1+0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1-i) * x) + (0.26e2 / 0.45e2) * ((-1-2*i) * t + (3-4*i) * y + t + (1+2*i) * x) * ((-1+2*i) * t + (3+4*i) * y + t + (1-2*i) * x) + (0.27783e5 / 0.1625e4+0.11619e5 / 0.1625e4*i) * ((-1-2*i) * t + (3-4*i) * y + t + (1+2*i) * x) * ((-0.2e1 / 0.3e1-i) * t + (0.5e1 / 0.9e1-0.4e1 / 0.3e1*i) * y + t + (0.2e1 / 0.3e1+i) * x) + (0.126229597e9 / 0.50430e5))

and the two line are

  eq1 = y == -0.9e1 / 0.28e2 * x - sqrt(0.3e1) * sqrt(0.15e2) / 0.14e2;
  eq2 = y == -0.1e1 / (a__2 ^ 2 + 2 * a__2 + 1) * (x + sqrt(0.3e1) * sqrt(-(a__2 * (a__2 ^ 2 + 1) ^ 3)) / (a__2 ^ 2 + 1)

and i take this out from the fig 1 from maple