I want to do a linear regression on the response Y (attached)with a predictor vector X. Therefore, I used Matlab polyfit function: [p,s,mu]=polyfit(X,Y,1) but it returns p=[NaN,Inf]
I have Inf values in vector Y. Is it the cause?

 채택된 답변

John D'Errico
John D'Errico 2015년 5월 18일
편집: John D'Errico 2015년 5월 18일

0 개 추천

Yes. infs in your data will surely cause NaNs, and essentially garbage results. Drop them out first if you expect something meaningful.
y = [rand(10,1);inf];
x = rand(11,1);
p = polyfit(x,y,1)
p =
NaN Inf
Surely you don't expect anything reasonable to come out of such a computation with INFs in it. What would the slope of such a line be with some data points at infinity? Of course, any such point at infinity would have infinite leverage.

추가 답변 (1개)

carlo lefevre
carlo lefevre 2015년 12월 9일

0 개 추천

ind = 1:length(a); k = ~isnan(a); p = polyfit(ind(k),a(k),n)

댓글 수: 1

Steven Lord
Steven Lord 2015년 12월 9일
You probably want to use ISFINITE instead of ~ISNAN to include only finite values (excluding Inf, -Inf, and NaN) rather than including only non-NaN values (which would NOT exclude Inf or -Inf.)

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Logical에 대해 자세히 알아보기

태그

질문:

2015년 5월 18일

댓글:

2015년 12월 9일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by