how to use categorical in uitable

조회 수: 6 (최근 30일)
Luca Re
Luca Re 2024년 10월 6일
댓글: Luca Re 2024년 10월 7일
hi, I want to choose as value in a table field 'Fil' or 'Stat'
cat=categorical({'Fil';'Stat'});
name={'A','B'};
nrows=numel(name);
VNAMES={'Draw';'Filt_Stat'};
VTYPES=[{'logical'},{cat}];
T=table('Size',[nrows,numel(VNAMES)],'VariableTypes',VTYPES,'VariableNames',VNAMES); % empty t
T.Draw=repmat({true},nrows,1);
ct=cell(1, numel(name));
ct(:) = {cat{2}};
T.Filt_Stat=ct';
app.Portfolio_UITable.Data=T;
i get this error:
Error using table
Specify variable types as a string array or a cell array of character
vectors, such as ["string", "datetime", "double"].

답변 (1개)

Walter Roberson
Walter Roberson 2024년 10월 6일
cat=categorical({'Fil';'Stat'});
That is categorical.
VTYPES=[{'logical'},{cat}];
That is a cell array that includes an element that is categorical.
T=table('Size',[nrows,numel(VNAMES)],'VariableTypes',VTYPES,'VariableNames',VNAMES); % empty t
VTYPES is a cell array that includes an element that is categorical. The VariableTypes parameter must be one of:
  • a string array
  • a cell array of character vectors
The result of categorical({'Fil';'Stat'}) is categorical, not a character vector.
When you set the VariableTypes, you can set an entry to be "categorical" or 'categorical' but you cannot set the entry to be a categorical
  댓글 수: 2
Walter Roberson
Walter Roberson 2024년 10월 7일
The VariableTypes parameter cannot hold any information about the details of categoricals.
What you might be thinking of is uitable . uitable() can have a ColumnFormat property, an element of which can be a cell array of character vectors that list category entries.
Luca Re
Luca Re 2024년 10월 7일
I already solved it thanks

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