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i have a column of data that has 100 points I also have a time column which only has 10 points basically data was sampled at 10Hz, but my time vector contains time value for every 10th sample.
How would I plot this? I run into a problem since the vectors are of different size.
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Baba
2011년 11월 17일
Walter Roberson
2011년 11월 17일
Duplicate is at http://www.mathworks.com/matlabcentral/answers/21564-plot
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bym
2011년 11월 17일
0 개 추천
use interp1 to resample your time vector to match the data vector
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Baba
2011년 11월 17일
bym
2011년 11월 17일
convert it using datenum perhaps?
Baba
2011년 11월 17일
bym
2011년 11월 17일
you can plot it using 'datetick' which plot is actual time value
Walter Roberson
2011년 11월 17일
If that is your "actual time vector" and the value after 200159 is 200200, then you do not appear to be missing any points.
If the first value in the vector of sampled time values is the time for the very first data point, then use
NewTimes = Time(1):Time(end)+9;
plot(NewTimes, Data);
If the first value in your vector of sampled times is instead the time for the 10th data point, then use
NewTimes = Time(1)-9:Time(end);
plot(NewTimes, Data);
Baba
2011년 11월 18일
Baba
2011년 11월 18일
bym
2011년 11월 18일
Am I interpreting you correctly: 200159 represents hh:mm:ss and you want to get hh:mm:ss.s ?
Baba
2011년 11월 18일
bym
2011년 11월 18일
then my original suggestion of converting to a datnum, using interp1, and plot using 'datetick' stands.
Baba
2011년 11월 18일
Walter Roberson
2011년 11월 18일
There is no method of creating empty spaces in a vector.
Note that if interp1() is used, use the 'linear','extrap' options.
You will also have to calculate the data point endpoints. But if you have already gone through the trouble of figuring out the endpoints, then you might as well use linspace()
Use the code from your other thread, but for the Time values, instead of passing in your 200159 and so on, pass in
Time = datenum(str2num(YourTimes.'));
and use the datetick suggestion,
datetick('x','HH:MM:SS.FFF')
카테고리
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