The cell with the max number of elements

I have 1x8 cell array and I want t get the cell with the max number of elements for example for the following cell array

I need the answer to be cell number 7 can I do this with function max?

Answer 1

[James Tursa]

>> c = {1 [1,2] [1,3] [1,2,4] [1,2,4,5] [1,6] [1,2,4,5,7] nan}
c = 
    [1]    [1x2 double]    [1x2 double]    [1x3 double]    [1x4 double]    [1x2 double]    [1x5 double]    [NaN]
>> [~,x] = max(cellfun(@numel,c))
x =
     7

[Maro]

thanks a lot

[Maro]

if I have 2x8 cell array and I want t get the cell with the max number of elements in each row for example for the following cell array

I need the answer to be cell number 7 for the first row and 4 for the second row

[James Tursa]

>> c(2,:) = {[1,2] nan nan [1,2,4,5,7] nan [1,6] [1,4] nan}
c = 
    [         1]    [1x2 double]    [1x2 double]    [1x3 double]    [1x4 double]    [1x2 double]    [1x5 double]    [NaN]
    [1x2 double]    [       NaN]    [       NaN]    [1x5 double]    [       NaN]    [1x2 double]    [1x2 double]    [NaN]

>> [~,x] = max(cellfun(@numel,c),[],2)
x =
     7
     4

[Maro]

if I have 4x8 cell array and I want to get the cell with the min number of elements in each row without including the NaN elements for example for the following cell array

I need the answer to be cell number 7 for the first row and 4 for the second row 2 1 3 4

[James Tursa]

Did you mean 2 for the first row and 1 for the second row?

[Maro]

sorry I need the answer to be 2 1 3 1... first row 2, second row 1, third row 1 forth row 1

[Titus Edelhofer]

Hi Maro,

this is the time I guess where a loop will be easier than trying to do this in a one liner, something like

res = zeros(1, size(c,2));
for i=1:length(res)
  val = c(:, i);
  % skip NaN
  idxNaN = find(~cellfun(@(x) numel(x)==1 && isnan(x), val, 'UniformOutput', true));
  % look for min in "allowed cells only"
  [~,x] = min(cellfun(@numel,val(idxNaN)));
  % be careful with the indices:
  res(i) = idxNaN(x);
end

Admittedly not tested ...

Titus

[Maro]

Hi, I have found more efficient solution..

   L=cellfun(@numel,c);
   L(L== 1) = Inf;
   [~,x]=min(L,[],2);