How to convert a table containing numbers and booleans to a double array?

조회 수: 4 (최근 30일)
using table2array I get a string array, but I need an array of numbers where the booleans become 0 or 1 respectivly. double(table2array(arr)) results in NaN for every boolean value
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the cyclist
the cyclist 2024년 7월 5일
편집: the cyclist 2024년 7월 5일
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hanspeter
hanspeter 2024년 7월 5일
whoops, I just noticed that the "booleans" weren't actual booleans, but string that were either "TRUE" or "FALSE". I was sure I checked that. With acutal booleans a simple table2array works just fine.
Anyway I attached an example table as the issue still persists. How do I convert this table to an array of doubles?

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Voss
Voss 2024년 7월 5일
편집: Voss 2024년 7월 5일
T = load('example.mat').data3
T = 1x2 timetable
time var1 var2 _____ _______ ____ 0 sec "FALSE" 2.52
M = [strcmpi(T.var1,'TRUE') T.var2]
M = 1x2
0 2.5200
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  댓글 수: 3
Voss
Voss 2024년 7월 5일
Here's one way to do that:
T = table(["FALSE";"TRUE";"FALSE";"FALSE"],[1.1;2.2;3.3;4.4],["TRUE";"TRUE";"FALSE";"TRUE"])
T = 4x3 table
Var1 Var2 Var3 _______ ____ _______ "FALSE" 1.1 "TRUE" "TRUE" 2.2 "TRUE" "FALSE" 3.3 "FALSE" "FALSE" 4.4 "TRUE"
[m,n] = size(T);
M = NaN(m,n);
for ii = 1:n
if isstring(T.(ii))
M(:,ii) = strcmpi(T.(ii),'TRUE');
else
M(:,ii) = T.(ii);
end
end
M
M = 4x3
0 1.1000 1.0000 1.0000 2.2000 1.0000 0 3.3000 0 0 4.4000 1.0000
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Walter Roberson
Walter Roberson 2024년 7월 5일
One approach would be to use
mask = varfunc(@isnumeric, T, OutputFormat = "uniform");
Output = zeros(height(T), width(T));
Output(:,mask) = T{:,mask};
Output(:,~mask) = varfunc(@(V)strcmpi(V, "TRUE"), InputVariables = ~mask, OutputFormat = "uniform");

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