Info
이 질문은 마감되었습니다. 편집하거나 답변을 올리려면 질문을 다시 여십시오.
solving equation in the time
조회 수: 1 (최근 30일)
이전 댓글 표시
hello, I have a program where I try to solve this system:
cos(theta)=cos(b)*[sin(f)*sin(d)+cos(d)*cos(f)*cos(w)]+sin(b)*[cos(d)*sin(g)*cos(w)*sin(f)-cos(g)*sin(d)*cos(f)+cos(d)*sin(w)*sin(g)] and
cos (theta) = cos (b) * sin (h) -cos (A) [sin (b) * cos (h) * cos (l)] - sin (a) * [sin (l) sin (b) * cos (h)]
such as: h, f, w, d, g, l are precalculated parameters changing during time; I try to extract every time ti,'a' and 'b' such that 0.98<cos (theta)<=1, I try with "solve" function but it gives that I haven't a digital result .... i try it also with lsqnonlin, but non result... have you proposed solution?
댓글 수: 0
답변 (0개)
이 질문은 마감되었습니다.
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!