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How can I process all the possible pairs of arrays without using 2 nested for loops?

조회 수: 3 (최근 30일)
I have a number of arrays and I want to compute a distance (using a home made function) between all possible pairs.
Right now I have 2 for loops like this
for i=1:(N-1)
for j=(i+1):N
applymyfunction (array(i), array(j))
end
end
I was wondering if there was a way to do this without using nested loops.
Thanks - F.
  댓글 수: 1
Stephen23
Stephen23 2024년 3월 18일
편집: Stephen23 2024년 3월 18일
I don't see any particular disadvantage in using loops:
  • loops are efficient,
  • the intent is clear,
  • debugging is easy,
  • your function will get called exactly how many times it needs to be called.
What is your specific reason for avoiding loops?

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답변 (1개)

Walter Roberson
Walter Roberson 2024년 3월 17일
if all(triu(FirstMatrix) == triu(SecondMatrix), 'all')
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FredMat
FredMat 2024년 3월 18일
편집: FredMat 2024년 3월 18일
Maybe "compare" was not the right word here.
I rewrote my question. Hopefully, it's more clear.
Walter Roberson
Walter Roberson 2024년 3월 18일
pdist2() or pdist(), specifying a function handle as the distance function.

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