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Curve fitter, how to start?

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Sergio
Sergio 2024년 2월 26일
댓글: Star Strider 2024년 2월 26일
Hi, I just imported curve fitter to the my MATLAB. I have these coordinates from the xls file , and I wish to import them directly in curve fitter. But that doesn't open it. Can this be done easily?
Any help appreciated
Thanks

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Star Strider
Star Strider 2024년 2월 26일
Try this —
T1 = readtable('data.xlsx');
Var1 = str2double(cellfun(@(x)regexp(x, '\d*', 'match'), T1.Var1));
T1 = removevars(T1,'Var1');
T1 = addvars(T1, Var1, 'Before','Var2')
T1 = 5×2 table
Var1 Var2 ____ ____ 39 167 40 192 41 240 42 343 43 497
fitf1 = fit(T1.Var1, T1.Var2, 'poly1')
fitf1 =
Linear model Poly1: fitf1(x) = p1*x + p2 Coefficients (with 95% confidence bounds): p1 = 81.1 (32.16, 130) p2 = -3037 (-5045, -1030)
figure
plot(fitf1, T1.Var1, T1.Var2)
grid
fitf2 = fit(T1.Var1, T1.Var2, 'poly2')
fitf2 =
Linear model Poly2: fitf2(x) = p1*x^2 + p2*x + p3 Coefficients (with 95% confidence bounds): p1 = 22.36 (14.35, 30.36) p2 = -1752 (-2409, -1096) p3 = 3.45e+04 (2.105e+04, 4.795e+04)
figure
plot(fitf2, T1.Var1, T1.Var2)
grid
.
  댓글 수: 2
Sergio
Sergio 2024년 2월 26일
Thanks, the exponential form was the desired! Thanks!
Star Strider
Star Strider 2024년 2월 26일
As always, my pleasure!
Not all the estimated parameters in the exponential or power functions were significantly different from zero (the confidence limits have opposite signs) so I only posted the models with significant parameters. (I tried several different models with 3 or fewer parameters, since there are only 4 data points, only models with 3 or fewer paramters will give reliable results in this instance.)

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