matrix convertion needs modification

I want to create a matrix with entries -1, 0, and 1 but it gives only -1 and 1, how to adjust

x = [9 3.6 9; 11 3.6 9; 9 4.4 9; 11 4.4 9; 9 3.6 11; 11 3.6 11;9 4.4 11; 11 4.4 11];
% convertion to -1,  0, and  1
V = ( x(:,1) - min(x(:,1)) )/(range(x(:,1))/2) - 1;  %% This line needs some modifications
% NOW convert to MATRIX (-1. 0,  and  1)  
% Below lines also need some modifications
X = [(x(:,1) - min(x(:,1)))/1 - 1    (x(:,2) - min(x(:,2)))/0.4 - 1     (x(:,3) - min(x(:,3)))/1 - 1]

X = 8×3

-1.0000 -1.0000 -1.0000 1.0000 -1.0000 -1.0000 -1.0000 1.0000 -1.0000 1.0000 1.0000 -1.0000 -1.0000 -1.0000 1.0000 1.0000 -1.0000 1.0000 -1.0000 1.0000 1.0000 1.0000 1.0000 1.0000

[Stephen23]

What value/s (or rows of values) should be mapped to zero?

Or more generally, what values should be mapped to -1, 0, 1 ?

[Dinesh]

Please explain what you are trying to achieve!

[MINATI PATRA]

like the output of,

dBB = bbdesign(3)

%% Can be found in https://in.mathworks.com/help/stats/bbdesign.html

Answer 1

[Matt J]

Perhaps this is what you had in mind?

x = [9 3.6 9; 11 3.6 9; 9 4.4 9; 11 4.4 9; 9 3.6 11; 11 3.6 11;9 4.4 11; 11 4.4 11];

X=rescale(x,-1,1,InputMin=min(x,[],2), InputMax=max(x,[],2)  )

X = 8×3

1.0000 -1.0000 1.0000 1.0000 -1.0000 0.4595 1.0000 -1.0000 1.0000 1.0000 -1.0000 0.3939 0.4595 -1.0000 1.0000 1.0000 -1.0000 1.0000 0.3939 -1.0000 1.0000 1.0000 -1.0000 1.0000

X(abs(X)<1)=0

X = 8×3

1 -1 1 0 -1 0 1 -1 1 1 -1 0 0 -1 0 0 -1 0 0 -1 1 1 -1 1

[MINATI PATRA]

looks right Matt, Thanks

I will check & Implement.

[MINATI PATRA]

Dear Matt J

Your idea needs some modification for the following work, Please get into:

('0' is not coming)

P = [T.p1 T.p2 T.p3]; x = P;

X = rescale( x,-1,1,InputMin = min(x,[],2), InputMax = max(x,[],2) );

X(abs(X)<1) = 0

[MINATI PATRA]

Here is the answer (attached pdf) to match the output.

[MINATI PATRA]

Dear Matt

Why here is an option "Moved"? I didnot get that.