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How to solve interdependent differtional equations

조회 수: 2 (최근 30일)
Ahmed Aburakhia
Ahmed Aburakhia 2023년 12월 9일
댓글: Sulaymon Eshkabilov 2023년 12월 9일
Hi
I have a system of three differetional equations
I defined my function as follow
function dydx = StratNoObs(x, y)
D=1; %depth [m]
rho_bs=2000;%[kg/m3]
rho_ts=1000;%[kg/m3]
drho_dy=rho_bs-rho_ts/D;
rho_t = rho_ts/(rho_bs*drho_dy); %
rho_b = rho_bs/(rho_bs*drho_dy); % [kg/m3]
U=1;
Ri = (9.81*D^2*drho_dy)/(U^2*rho_bs);
Re = 100;
diffusifty = 0.000025; %[m2/s]
mu = 0.001002; % [kg/(m.s)]
Sc= (mu/(rho_bs*diffusifty)); %the ratio of the coefficient of diffusion to the kinematic viscosity
d_rho=rho_t/rho_b;
b = y(1);
f = y(2);
e = y(3);
dbdx = (280.*e+(1400/3).*f)./(Ri*Re);
fA = -(2.*f)./(Re);
fB = -Ri*(-4/735).*dbdx;
fC = (1/Re).*(-(1/3).*e-(2/9).*f);
fD = -((13/11340).*e+(31/17010).*f+(1/90));
fF = -dbdx*((-21*.e-41*.f-1404)./(882.*(rho_b-rho_t+(1/42).*b)));
fG = -(1080.*b)./(Re.*Sc.*(42.*rho_b-42.*rho_t+(1/42).*b));
fI = -(1470.*rho_b-1470.*rho_t+41.*b)/(882.*rho_b-882.*rho_t+21.*b);
fJ = ((31/17010).*e+(76/25515).*f+(1/54));
dfdx = (fA+fB+fC+fD.*(fF+fG)./(-fD.*fI+fJ);
dedx = fI.*dfdx+fF+fG;
dydx = [dbdx; dfdx; dedx];
end
I am not getting the expected answer so is I am questioning if it is ok to call the dbdx and dfdx in the defintion dedx?
Thank you

답변 (1개)

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2023년 12월 9일
Here is the corrected code. There were a few syntx errs and missing paranthesis.
x= linspace(0, pi);
y = [0 1 -1];
SOL=StratNoObs(x, y)
SOL = 3×1
1.0e+05 * 0.0000 -4.9307 8.2301
function dydx = StratNoObs(x, y)
D=1; %depth [m]
rho_bs=2000;%[kg/m3]
rho_ts=1000;%[kg/m3]
drho_dy=rho_bs-rho_ts/D;
rho_t = rho_ts/(rho_bs*drho_dy); %
rho_b = rho_bs/(rho_bs*drho_dy); % [kg/m3]
U=1;
Ri = (9.81*D^2*drho_dy)/(U^2*rho_bs);
Re = 100;
diffusifty = 0.000025; %[m2/s]
mu = 0.001002; % [kg/(m.s)]
Sc= (mu/(rho_bs*diffusifty)); %the ratio of the coefficient of diffusion to the kinematic viscosity
d_rho=rho_t/rho_b;
b = y(1);
f = y(2);
e = y(3);
dbdx = (280.*e+(1400/3).*f)./(Ri*Re);
fA = -(2.*f)./(Re);
fB = -Ri*(-4/735).*dbdx;
fC = (1/Re).*(-(1/3).*e-(2/9).*f);
fD = -((13/11340).*e+(31/17010).*f+(1/90));
fF = -dbdx*((-21.*e-41.*f-1404)./(882.*(rho_b-rho_t+(1/42).*b)));
fG = -(1080.*b)./(Re.*Sc.*(42.*rho_b-42.*rho_t+(1/42).*b));
fI = -(1470.*rho_b-1470.*rho_t+41.*b)/(882.*rho_b-882.*rho_t+21.*b);
fJ = ((31/17010).*e+(76/25515).*f+(1/54));
dfdx = (fA+fB+fC+fD.*(fF+fG))./(-fD.*fI+fJ);
dedx = fI.*dfdx+fF+fG;
dydx = [dbdx; dfdx; dedx];
end
  댓글 수: 2
Ahmed Aburakhia
Ahmed Aburakhia 2023년 12월 9일
thanks for correcting my code. I am more concern with the methodolagy as I am not famialir with a system of ODEs. I took the matlab course but their ODEs are not interdependant. In my case I am using dbdx in solving for dfdx and using both dbdx and dfdx in solving for dedx. Is this the correct way?
Sulaymon Eshkabilov
Sulaymon Eshkabilov 2023년 12월 9일
Just looking at only math operations and manipulated variables here, all steps are legit. But it is said without seeing your original diff equations.

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