I code a bisection method on MATLAB app designer, how can I fix this error ?
조회 수: 3 (최근 30일)
이전 댓글 표시
typefunction = app.TypefunctionEditField.Value;
a = app.aEditField.Value
b = app.bEditField.Value
run = app.RunButton.ButtonPushedFcn
error= app.errorEditField.Value
fxi=str2func(['@(x)'typefunction]);
number_of_iterations=0;
if fxi(a)*fxi(b)>0
result=NaN;
return
end
if fxi(a)==0
result=a;
return
elseif fxi(b)==0
result=b;
return
end
while(abs(a-b)>=error)
result=(a+b)/2;
if fxi(a)*fxi(result)<0
b=result;
else
a=result;
end
number_of_iterations=number_of_iterations+1;
end


댓글 수: 1
답변 (1개)
Walter Roberson
2023년 11월 30일
fxi=str2func(['@(x)'typefunction]);
You need a space or comma, like
fxi=str2func(['@(x)' typefunction]);
댓글 수: 2
Walter Roberson
2023년 11월 30일
I copied your posted code into the editor, and added in the one space that I indicate, and that cleared up the error message. There are still warnings recommending that you add in semi-colons to prevent unnecessary output, but the error is gone just by putting in that one space.
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!