Array notation instead of iterative loop for difference equation

Hi, I have somehow a difference equation and wanted to improve the speed of my code and calculate it directly through arrays instead of an iterative loop.

I have a container that is continuously filled. It is emptied at certain times.

I would like to have the mass at each time step of the container.

With an iterative loop I calculated it:

% Dummy values for the incomming mass

m_new = randi(50,288,1);

% Time slots to empty the container

m_empty = false(size(m_new));

m_empty([60,60+96, 60+2*96]) = true;

% Use the mass of the previous time step unless the container has been emptied

contents_remaining = xor(true, m_empty);

% Initializing my array for the loop

mm = zeros(size(m_new));

% Initialize my array with a start value

mm(1) = 300;

% For each time step, calculate the content from the previous time step and the newly added mass.

for i = 1:size(m_new,1)-1

mm(i+1) = mm(i) * contents_remaining(i) + m_new(i);

end

Is it possible to perform this calculation without a for loop?

Unfortunately, I have not come up with a satisfactory result and hope you can help me to avoid the for loop.

[Dyuman Joshi]

m_new = randi(50,size(m_new));

Something is not right here.

Also, given the operations performed in the code above, it seems mm should be prellocated as a vector, instead of a square matrix.

[Torsten]

The answer given here still holds:

https://uk.mathworks.com/matlabcentral/answers/391818-recursive-computation-without-loop

[Julian]

@Dyuman Joshi I have mixed up the line of m_new and m_empty

@Torsten Ok, that means I wasn't on the wrong track, but there is no better solution to the problem.

[Dyuman Joshi]

I don't see a problem with this approach.

[Stephen23]

"Is it possible to perform this calculation without a for loop?"

Why?

[Torsten]

Ok, that means I wasn't on the wrong track, but there is no better solution to the problem.

Yes, recursions are hard (or even impossible ?) to vectorize.