Data type converts from integer to array

When I run the code below, I get an error that the index is not an integer value. Instead, my variable 'r' goes from being an integer to a 1x24 array. Why is this?

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R = 1:0.25:6.75;
r = 1;
p = 0;
pout = 0;
Rn = 0;
record = zeros(100, 24);
Pout = zeros(31, 24);
for i = 1:100
    for j = 1:24
        if r < 6.75
            Rn = 4 * r - 3;     %Converts ECR to its index
            pout = Pout(j, Rn); %Retrive's outage probability
            p = randi([0 100], 1) / 100;
            if p <= pout
                r = floor(2 * R) / 4;
            else
                r = r + 0.25;
            end
        elseif r == 6.75
            Rn = 4 * r - 3;     %Converts ECR to its index
            pout = Pout(j, Rn); %Retrive's outage probability
            p = randi([0 100], 1) / 100;
            if p <= pout
                r = floor(2 * R) / 4;
            end
        end
    end
    record(i, j) = r;
end

Answer 1

[Walter Roberson]

Because R is a vector and you have

                r = floor(2 * R) / 4;

which uses the vector R and assigns the result to r making r the same size as R ?

[Eric Lopez]

Thank you! These little things I just don’t notice enough as I should.