3D hexagonal mesh grid

Hi,

I arranged the x-y space in hexagonal format as a layer. How can I add another similar layer on top with a distance in the z-direction?

I appreciate your help.

Thanks a lot,

Answer 1

[Matt J]

V=nsidedpoly(6).Vertices;

[X,Z]=ndgrid(V(:,1),0:3);
[Y,~]=ndgrid(V(:,2),0:3);

scatter3(X(:),Y(:),Z(:)); view(-60,70)
xlabel X; ylabel Y; zlabel Z

[S. Hannan]

I arranged the x-y system with the code bellow:

m = 6;

n = 7;

[x,y] = meshgrid(0:m, 0:n);

X = (3*x - mod(x+y,2)) / 2;

X=X+0.5;

X=X(4:8,1:4);

Y = (sqrt(3)/2)*y;

Y=Y(4:8,1:4);

Y=Y-Y(1,1);

plot(X,Y,'or');

As you can see, it is shown in a 2D space. Now, I want to show it in a 3D space with various z values (z is constant for each layer) using this code:

m = 6;

n = 7;

[x,y,z] = meshgrid(0:m, 0:n, 0:1);

x = (3*x - mod(x+y,2)) / 2;

x = x+0.5;

x = x(4:8,1:4,:);

y = (sqrt(3)/2)*y;

y=y(4:8,1:4,:);

y=y-y(1,1);

z=z(4:8,1:4,:);

[Dyuman Joshi]

What is the expected output?

[S. Hannan]

Showing a multilayer system.

[Dyuman Joshi]

It would help to have a visual example of the expected output.

From what I understood of the provided description -

m = 6;
n = 7;
[x,y] = meshgrid(0:m, 0:n);
X = (3*x - mod(x+y,2)) / 2;
X=X+0.5;
X=X(4:8,1:4);
Y = (sqrt(3)/2)*y;
Y=Y(4:8,1:4);
Y=Y-Y(1,1);
X = X(:);
Y = Y(:);
z_values = [0 0.5 1];

figure
for k=z_values
    plot3(X,Y,k*ones(size(X)),'o','Color', rand(1,3))
    hold on
end

%end
hold off

Do you want to join the dots in each 2D layer?

[S. Hannan]

Thanks a lot.

No, I don't need to connect them.

[Matt J]

Now, I want to show it in a 3D space with various z values (z is constant for each layer) using this code:

I don't know what you think this changes about my answer. Isn't this what you want?

m = 6;
n = 7;
[x,y] = meshgrid(0:m, 0:n);
X = (3*x - mod(x+y,2)) / 2;
X=X+0.5;
X=X(4:8,1:4);
Y = (sqrt(3)/2)*y;
Y=Y(4:8,1:4);
Y=Y-Y(1,1);

V=[X(:),Y(:)];

[X,Z]=ndgrid(V(:,1),0:3);
[Y,~]=ndgrid(V(:,2),0:3);

scatter3(X(:),Y(:),Z(:)); view(-70,83)
xlabel X; ylabel Y; zlabel Z

[S. Hannan]

Thanks a lot.

Yes. this is the desired structure.