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App designer - problem implementing filter based on tree nodes

조회 수: 6 (최근 30일)
Teshan Rezel
Teshan Rezel 2023년 6월 27일
댓글: Teshan Rezel 2023년 7월 10일
Hi folks,
i have a tree that looks something like this:
I am trying to createn a filter based on "cause" whereby you can see things on a table to the left based on one or more of the selected criteria (such as fire, or fire + attack).
So I've used the following code from another thread (below). However, I am getting the error "Unrecognized method, property, or field 'Cause' for class 'matlab.ui.control.Table'. Is there a way around this please?
function [filter_criteria, checked_nodes] = get_checked_nodes(~, checked)
% checked = checked nodes object from tree
% if tr = tree, checked=tr.CheckedNodes
% filter_criteria = structure with variables and values objects,
% each record has the name of the variable in variables as a string and a string array of the values for those items checked in the nodes.
% checked_nodes = table with all checked nodes. Table Structure includes node level (only level 2 is included),
% Parent (variable name), and leaf (selected string option in tree).
% If the parent node is checked, the values will not be returned, because all records would be returned and there are no criteria to filter on.
if size(checked,1)==0
filter_criteria=[];
checked_nodes=[];
return
end
node_num=size(checked,1);
checked_nodes=table(Size=[ node_num 3],VariableTypes=["double" "string" "string"],VariableNames=["node_level" "parent_node" "leaf"]);
for node_id=1:node_num
if checked(node_id).Parent.Type~="uitreenode" % if parent node is not uitreenode, then top level
checked_nodes.node_level(node_id)=1;
checked_nodes.parent_node(node_id)=checked(node_id).Text; % parent nodes have themselves as parent here
checked_nodes.leaf(node_id)=checked(node_id).Text;
else
checked_nodes.node_level(node_id)=2;
checked_nodes.parent_node(node_id)=checked(node_id).Parent.Text;
checked_nodes.leaf(node_id)=checked(node_id).Text;
end
end
check_parents=checked_nodes.leaf(checked_nodes.node_level==1);
node_rows=~ismember(checked_nodes.parent_node,check_parents);
checked_nodes=checked_nodes(node_rows,:); % removes parents from checked_nodes
clear filter_criteria
varnames=unique(checked_nodes.parent_node);
for varnum=1:size(varnames,1)
filter_criteria(varnum).variables=varnames(varnum);
filter_criteria(varnum).values=checked_nodes.leaf(checked_nodes.parent_node==varnames(varnum))';
end
end
function [filtered_rows] = get_filtered_rows(~,source_table, filter_criteria)
% create a logical array of filtered rows based upon a source table and filter criteria.
% The array can then be used to select specific rows from a table or array.
% The filter criteria selects fields that have any option in the values within a field,
% but if multiple fields are used, the row must be selected for each variable used in the filter.
if isempty(filter_criteria)
filtered_rows=true(size(source_table,1),1);
return;
end
num_vars=size(filter_criteria,2);
filtered_matrix=[];
for varnum=1:num_vars
filtered_matrix(:,varnum)=ismember(source_table.(filter_criteria(varnum).variables),filter_criteria(varnum).values);
end
filtered_rows=all(filtered_matrix,2);
end

채택된 답변

Kevin Holly
Kevin Holly 2023년 6월 27일
Teshan,
I created an app based on the scripts provided (see attached). Please let me know if this answers your question. I believe you were inputing the incorrect variable as the source_table into the get_filtered_rows function.
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