필터 지우기
필터 지우기

how to determine that all cell array value exists in other cell array?

조회 수: 36 (최근 30일)
Mira le
Mira le 2023년 6월 14일
댓글: Mira le 2023년 6월 15일
Hello every one
I have a cell array
S=3×1 cell array
[ 29 56 62]
[34 40 62]
[48 52 7]
and other sequence of values in cell array
T{1} for examle:
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74
Hiw can I check that all values in S are contain in T?
Thank you
  댓글 수: 1
the cyclist
the cyclist 2023년 6월 14일
To save anyone else who looks at this from the effort:
S = {[29 56 62];
[34 40 62];
[48 52 7]};
T = {[1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74]};

댓글을 달려면 로그인하십시오.

채택된 답변

the cyclist
the cyclist 2023년 6월 14일
This does what I think you want:
S = {[29 56 62];
[34 40 62];
[48 52 7]};
T = {[1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74]};
allSinT = cellfun(@(x,y) all(ismember(x,y),2), S,repmat(T,size(S)))
allSinT = 3×1 logical array
1 1 1

추가 답변 (1개)

Samya
Samya 2023년 6월 14일
편집: Samya 2023년 6월 14일
To check if all the values of S are contained in T, you can use the ismember function.
Here's the code to check if all values in S are contained in T{1} specifically:
all(ismember(S{1}, T{1}))
This will return a logical value of true if all the values in S{1} are contained in T{1} and false otherwise.
If you have multiple sequences in T and you need to check if all values in S are contained in any of them, you can use a loop like this:
all_included = false;
for i=1:length(T)
if all(ismember(S{i}, T{i}))
all_included = true;
break;
end
end
This will return a logical value of true in all_included if all the values in S are contained in any of the sequences in T, and false otherwise.
Hope this helps!

카테고리

Help CenterFile Exchange에서 Matrices and Arrays에 대해 자세히 알아보기

제품


릴리스

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by