Explicitly specifying line colors when plotting a matrix
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이전 댓글 표시
x = 1:3;
y = [1 2 3; 42 40 34];
plot(x,y,'Color', [0.5 0.5 0.5; 1 0 0])
produce an error:
Error using plot
Color value must be a 3 element numeric vector
Same with:
plot(x,y,'rg')
Error using plot
Error in color/linetype argument
This has bugged me for years, but I have circumvented it by unrolling the matrix into a number of vectors that I plot one at a time using whatever color I prefer. But is there no way to tell MATLAB (in a compact, readable form) what colors I would like it to use for whatever number of lines it will plot?
댓글 수: 1
ELTH
2016년 8월 16일
You can make a for loop and specify each line's colour based on the RGB code:
x = 1:3;
y = [22 20 18; 32 30 24; 42 40 34];
figure
hold on
for k=1:size(y,1)
p(k)=plot(x,y(k,1:end),'LineWidth',2);
set(p(k),'Color',[(size(y,1)-k+1)/size(y,1) k/size(y,1) 0.1]);
end
채택된 답변
Kelly Kearney
2017년 1월 10일
An alternative method would be to save the handles of the plotted data and set the colors via the array option of set. I find this method a lot less hassle than messing with ColorOrder and hold states:
x = 1:3;
y = [1 2 3; 42 40 34];
h = plot(x,y);
set(h, {'color'}, {[0.5 0.5 0.5]; [1 0 0]});
I often use the shortcut of using a colormap with num2cell to get the desired list of colors:
set(h, {'color'}, num2cell(jet(2),2));
댓글 수: 7
Simon Silge
2021년 11월 26일
편집: Simon Silge
2021년 11월 26일
Since 2019 there is an easier way to do this by setting your own color order by using the colororder command.
x = 1:3;
y = [1 2 3; 42 40 34];
colororder([0 0 1; 0.5 0.6 0])
plot(x,y)
Aaron Drews
2023년 6월 13일
Building on @Simon Silge's response, one can also use colororder with the preset colors (e.g., 'k', 'r', 'b', etc) if they're provided as a cell array:
x = 1:3;
y = [1 2 3; 42 40 34];
colororder({'r', 'b'})
plot(x, y)
추가 답변 (3개)
Image Analyst
2011년 10월 30일
In the help it says this:
"plot automatically chooses colors and line styles in the order specified by ColorOrder and LineStyleOrder properties of current axes. ColorOrder : m-by-3 matrix of RGB values
Colors to use for multiline plots. Defines the colors used by the plot and plot3 functions to color each line plotted. If you do not specify a line color with plot and plot3, these functions cycle through the ColorOrder property to obtain the color for each line plotted. To obtain the current ColorOrder, which might be set during startup, get the property value:
get(gca,'ColorOrder')
Note that if the axes NextPlot property is replace (the default), high-level functions like plot reset the ColorOrder property before determining the colors to use. If you want MATLAB to use a ColorOrder that is different from the default, set NextPlot to replacechildren. You can also specify your own default ColorOrder."
co = get(gca,'ColorOrder') % Initial
% Change to new colors.
set(gca, 'ColorOrder', [0.5 0.5 0.5; 1 0 0], 'NextPlot', 'replacechildren');
co = get(gca,'ColorOrder') % Verify it changed
% Now plot with changed colors.
x = 1:3;
y = [1 2 3; 42 40 34];
plot(x,y, 'LineWidth', 3);
The things I put in the set() command are especially important.
댓글 수: 6
Cici Ma
2017년 1월 9일
A note for subplot: need to put the set line before each plot command
x = 1:3;
y1 = [1 2 3; 42 40 34];
y2 = [3 5 8; 11 17 29];
subplot(2,1,1);
set(gca, 'ColorOrder', [0.5 0.5 0.5; 0.2 0.2 0.2],'NextPlot', 'replacechildren');
plot(x,y1, 'LineWidth', 3);
subplot(2,1,2);
set(gca, 'ColorOrder', [0.5 0.5 0.5; 0.2 0.2 0.2],'NextPlot', 'replacechildren');
plot(x,y2, 'LineWidth', 3);
And much appreciated to Image Analyst!
Daniele Maddaluno
2017년 12월 8일
편집: Daniele Maddaluno
2017년 12월 8일
I can solve your problem with something like this:
x = 1:5;
y = [x; x.^2; x.^3; x.^4; x.^5];
n = size(y, 1);
colors = hsv(n);
h = plot(x, y);
set(h, {'color'}, num2cell(colors, 2));
댓글 수: 2
Vivek Bhardwaj
2019년 2월 14일
Hi, works perfectly, thank you. I have a follow-up question to this. Is it possible that I can have the colors based on a different data set? i.e. I use X and Y only for plotting but the colors of the plot are based on data set, say P (Pressures).
Joakim Wang Erlandsson
2018년 9월 19일
It is beyond me how matlab manages to be so unintuitive in the most simple sitiations. Luckily there is a smart community that can find workarounds for all of these shortcomings. Someone above stated happily that this answer is still helping people years after it was asked, too me this is just sad, that Mathworks haven't improved this in all of that time.
댓글 수: 3
Jolanda Müller
2023년 9월 25일
I agree with you, Joakim. I think by now it should be possible to do something like "plot(x,Y, 'color', C), where Y is a matrix, and C contains as many colors as there will be lines.
Image Analyst
2023년 9월 25일
@Jolanda Müller you simply need to call the colororder function first before calling plot, instead of passing your colors into plot. It's hardly a horrendous hassle or even a "workaround". It's just a different way of doing things and only requires one line of code to tell it to use your custom colors.
numCurves = 20;
numPointsPerCurve = 10;
% Create matrix of data. Individual curves are in columns.
M = rand(numCurves, numPointsPerCurve);
% Create matrix of custom colors for each curve.
C = rand(numCurves, 3); % Just random colors.
colororder(C); % Tell MATLAB to use these custom colors.
% Plot 20 curves, each with it's own unique custom color.
plot(M, '.-', 'LineWidth', 2)
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