how to consider only the integer part discarding the exponent part

Suppose i have a= [1 23 56]*10^(-9);

i want to acccess only the integer part that is 1 23 and 56.

i want to find the max(a). That is the output should be 56.

Answer 1

[Pramil]

What you can do is multiply "a" with 10^9 first and then proceed to find max(a). Like this :

a = [1 23 56]*10^(-9); % given array
a_int = int64(a*10^9); % convert to integer array
max_a = max(a_int); % find maximum value
disp(max_a);

   56

Answer 2

[Star Strider]

This appears to be a reasonably robust approach —

a = [1 23 56]*10^(-9);
b = a.*10.^ceil(-log10(abs(a))+1)

b = 1×3

10.0000 23.0000 56.0000

max_a = max(b)

max_a = 56.0000

a = [1 23 56]*10^(-6);
b = a.*10.^ceil(-log10(abs(a))+1)

b = 1×3

10 23 56

a = [1 23 56]*10^(10);
b = a.*10.^ceil(-log10(abs(a))+1)

b = 1×3

10 23 56

a = [1 23 56]*10^(-1);
b = a.*10.^ceil(-log10(abs(a))+1)

b = 1×3

10.0000 23.0000 56.0000

EDIT — Corrected typographical error

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