three order complex coefficient polynomial root matlab
이전 댓글 표시
Hi, I would like to find the root for a 3rd order polynomial with complex coefficient.
The polynomial is like:
28x^3 + Ax^2 + Bx - C = 0;
A,B,C are complex numbers.
I appreciate if anyone can help.
답변 (3개)
There are at least two options —
z = complex(randn(3,1), randn(3,1))
r = roots([28; z])
syms x
p = 28*x.^3 + z(1,:)*x.^2 + z(2,:)*x + z(3,:);
vpap = vpa(p, 5)
r = vpa(solve(p), 5)
.
John D'Errico
2023년 5월 26일
1 개 추천
Another classic solution is to find the matrix that has the same eigenvalues as your polynomial has roots. Then use eig to compute the eigenvalues of this "companion matrix". This is in fact what roots does.
syms x A B C
eqn = 28*x^3 + A*x^2 + B*x - C == 0;
solutions = solve(eqn, x, 'MaxDegree', 3)
char(solutions(1))
char(solutions(2))
char(solutions(3))
카테고리
도움말 센터 및 File Exchange에서 Polynomials에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

